Quant Quiz

1. Find remainder of (7^99)/6

1) 2 

2) 1 

3) 4 

4) 3 

5) None of these

2. What is the greatest number of 4 digits that when divided by any of the numbers 6, 9, 12, 17 leaves a remainder of 2?

1) 9792 

2) 9982 

3) 9794 

4) 9906 

5) None of these

3. In a fraction, numerator is increased by 20% and the denominator is diminished by 30%. The new fraction obtained is 2/3. The original fraction is:

1) 7/18

2) 5/9

3) 6/11

4) 3/5

5) None of these

4. Find a single discount equivalent to a discount series of 25%, 20%, 10%-

1) 23% 

2) 46% 

3) 48% 

4) 55% 

5) 50%

5. By selling pen for ` 81, a shopkeeper gain 35%. At what price should he sell the pen to gain 20% on the cost price?

1) Rs. 72 

2) Rs. 66 

3) Rs. 92 

4) Rs. 76 

5) None of these

Answers

1.      2         

2. 3

LCM of 6, 9, 12, 17 = 612

Greatest Number of 4 digit divisible by 612 is 9792, to get remainder 2 number should be = 9792 + 2 = 9794

3. 1

4. 2

5. 1

Notes

For question 1& remainder prblms...
Case 1...If. (a+1)^n/a then remainder always = 1
Case. 2..If a^n/(a+1)..then rem..
If power is odd thn = a
If even than = 1
Case 1...If. (a+1)^n/a then remainder always = 1
Ex. 8^99/7 = (7+1)^99/7
In that case answer always 1..
Case. 2..If a^n/(a+1)..then rem..
If power is odd thn = a
= 7^99/8 = 7^99 / (7+1)
Than and is a = 7
If even than = 1
= 7^98/8 = 7^98 / (7+1)
Ans. is always 1