1.Rs.6,000 becomes Rs. 6,720 in a year at SI. What will Rs. 9,600
become at the end of three years at the same rate of simple interest?
(a) Rs. 13,056
(b) Rs. 14, 048
(c) Rs. 15, 024
(d) Rs. 16, 014
2.The number nearest to 27987 which is divisible by 43 is .
(a) 27950
(b) 27962
(c) 27981
(d) 27993
3.Two metallic cylinders of heights 5 cm and 4 cm and both having
the same base radii of 2 cm are melted to form a sphere. Find the radius
of the sphere.
(a) 2 cm
(b) 3 cm
(c) 4 cm
(d) 5 cm
4.If a^4 – b^4 = 65 and a – b = 1, where a and b are positive
integers, then the value of (a^2 + b^2) is _________ .
(a) 13
(b) 15
(c) 17
(d) 19
5.A Shopkeeper offered a discount of 15% on a certain product and
gained a profit of 20%. If the marked price is Rs. 13800, then what is the
profit earned by the shopkeeper?
(a) Rs. 1215
(b) Rs. 1505
(c) Rs. 1955
(d) Rs. 2405
6.If (4x^2 + 7y^2) : 2 x y = 16 : 3 then the value of (x + y)/(x –
y) which is not a multiple of 5 is _
(a) 7
(b) 11
(c) 13
(d) None of these.
7.The monthly salary of Kishore is Rs. 15, 000. His salary is
increase by 8%. His expenditure is increased by Rs. 720 which is 6% of the
previous expenditure. The savings of Kishore after the increase is
__________.
(a) Rs. 3, 240
(b) Rs. 3, 480
(c) Rs. 3, 600
(d) Rs. 3, 720
8.Find the next number of the following series.
9, 10, 19, 44, 93, __________
(a) 174
(b 180
(c) 186
(d) 192
9.A shopkeeper gave a discount of Rs. 30 on a product such that
the discount percentage is same as the profit percentage. If the cost price of
the product is Rs. 100, find the selling price of the product.
(a) Rs.112
(b) Rs. 150
(c) Rs. 130
(d) Rs. 120
10.A vegetable vendor bought 10 kg of tomatoes for Rs. 100 and
sold them at a rate of 8 kg for Rs. 120. The profit percentage of the vendor is
________.
(a) 20%
(b) 25%
(c) 40%
(d) 50%
ANSWERS AND SOLUTION:
1(a)Let'r" be the rate of intrest.
=>6000(1+r/100)= 6700
=>1+r/100= 6720/6000
=>1 + r/100 = 1.12
=>r/100=1.12-1= 0.12
r=(100)(.12)=12%
so 9600 in three years
=9600(1+(3x12)/100)
=9600(1.36)=Rs.13056
2(d)we have
27987 = 43(650) + 37
and 27987=43(651)-6
so 27993 is nearest to 27987 and is divisibleby 43
3(b)
Let "r" be the radius of the sphere,
The total volume of the two cylinder is equal to volume of the sphere formed.
=>π r1^2 h1^2 + π r2^2 h2=4/3πr3^3
=>4/3πr^3 = π(2)^2x5+π(2)^2x4
=>4/3r^3 = 20+16
=4/3r^3 =36
=>r^3 = 9x3=27
r=3
so The radius of the sphere formed is 3cm.
4(a)
Given that,a^4-b^4=65
a-b=1
a^4-b^4=(a^2-b^2)(a^2+b^2)
=(a-b)(a+b)(a^2+b^2)
=(a+b)(a^2+b^2)=65
we have
65=1x65 or 5x13
=>(a+b)(a^2+b^2)5x13
(a and b are positive integers,a-b=1 and a+b>1)
=a+b =5, a^2+b^2=12
a=2;b=3 or a=3,b=2
so a^2+b^2=13.
5(c) From the given data, SP = 85% of M.P
From the given data,SP= 85%of M.P
=85/100x13800=Rs.(85x138)
we know,profit = SP-CP
=SP-100/120SP = SP(1-100/120)
=85x138x20/120 = Rs.1955
6(c)
Given that
(4x^2+7y^2):2xy=16:3
=>3(4x^2 + 7y^2)=16 X 2xy
=>12x^2 + 21y^2 = 32xy
=>12x^2-32xy+21y^2=0
=>(6x-7y)(2x-3y) = 0
=>x/y=7/6 or 3/2
for x/y=7/6,(x+y)/(x-y) = (7+6)/(7-6)=13
for x/y=3/2,(x+y)/(x-y) = (3+2)/(3-2)=5
But (x+y)/(x-y)is not a multiple of 5=>(x+y)/(x-y)=13
7(b)
8(a)
9(d)
10(d)
The cost price of 1kg of tomatoes=100/10=10
The selling price of 1kg of tomatoes= 120/8=15
so The profit percentage obtained by him=(15-10)/10x100 =50%
1(a)Let'r" be the rate of intrest.
=>6000(1+r/100)= 6700
=>1+r/100= 6720/6000
=>1 + r/100 = 1.12
=>r/100=1.12-1= 0.12
r=(100)(.12)=12%
so 9600 in three years
=9600(1+(3x12)/100)
=9600(1.36)=Rs.13056
2(d)we have
27987 = 43(650) + 37
and 27987=43(651)-6
so 27993 is nearest to 27987 and is divisibleby 43
3(b)
Let "r" be the radius of the sphere,
The total volume of the two cylinder is equal to volume of the sphere formed.
=>π r1^2 h1^2 + π r2^2 h2=4/3πr3^3
=>4/3πr^3 = π(2)^2x5+π(2)^2x4
=>4/3r^3 = 20+16
=4/3r^3 =36
=>r^3 = 9x3=27
r=3
so The radius of the sphere formed is 3cm.
4(a)
Given that,a^4-b^4=65
a-b=1
a^4-b^4=(a^2-b^2)(a^2+b^2)
=(a-b)(a+b)(a^2+b^2)
=(a+b)(a^2+b^2)=65
we have
65=1x65 or 5x13
=>(a+b)(a^2+b^2)5x13
(a and b are positive integers,a-b=1 and a+b>1)
=a+b =5, a^2+b^2=12
a=2;b=3 or a=3,b=2
so a^2+b^2=13.
5(c) From the given data, SP = 85% of M.P
From the given data,SP= 85%of M.P
=85/100x13800=Rs.(85x138)
we know,profit = SP-CP
=SP-100/120SP = SP(1-100/120)
=85x138x20/120 = Rs.1955
6(c)
Given that
(4x^2+7y^2):2xy=16:3
=>3(4x^2 + 7y^2)=16 X 2xy
=>12x^2 + 21y^2 = 32xy
=>12x^2-32xy+21y^2=0
=>(6x-7y)(2x-3y) = 0
=>x/y=7/6 or 3/2
for x/y=7/6,(x+y)/(x-y) = (7+6)/(7-6)=13
for x/y=3/2,(x+y)/(x-y) = (3+2)/(3-2)=5
But (x+y)/(x-y)is not a multiple of 5=>(x+y)/(x-y)=13
7(b)
8(a)
9(d)
10(d)
The cost price of 1kg of tomatoes=100/10=10
The selling price of 1kg of tomatoes= 120/8=15
so The profit percentage obtained by him=(15-10)/10x100 =50%
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