Prime number : A prime number is a natural number greater
than 1 that has no positive divisors other than 1 and itself.
For example, 2, 3, 5, 7, 11, 13, etc. are prime numbers.
Co-Prime Number: Two numbers are said to be relatively prime,
mutually prime, or co-prime to each other when they have no common factor or
the only common positive factor of the two numbers is 1.In other words, two
numbers are said to be co-primes if their H.C.F. is 1.
Factors: The numbers are said to be factors of a given number when they
exactly divide that number.
Thus, factors of 18 are 1, 2, 3, 6, 9 and 18.
Common Factors: A common factor of two or more numbers is a
number which divides each of them exactly.
Thus, each of the numbers - 2, 4 and 8 is a common factor of 8 and
24.
Multiple: When a number is exactly divisible by another
number, then the former number is called the multiple of the latter number.
Thus, 45 is a multiple of 1, 3, 5, 9, 15 and 45.
Common Multiple: A common multiple of two or more numbers is a
number which is exactly divisible by each of them.
For example, 12, 24 and 36 is a common multiple of 3, 4, 6 and 12.
Prime Factorisation: If a natural number is expressed as the
product of prime numbers, then the factorisation of the number is called its
prime factorisation.
A prime factorisation of a natural number can be expressed in the
exponential form.
For example:
(1) 24 = 2 x 2 x 2 x 3 = 2^3 x 3.
(2) 420 = 2 x 2 x 3 x 5 x 7 = 2^2 x 3 x 5 x 7
Highest Common Factor (H.C.F.) or Greatest
Common Divisor (G.C.D.) or Greatest Common Measure (G.C.M.) are synonymous terms:
The H.C.F of two or more than two numbers is the greatest numbers
which divides each of them without any remainder.
Methods of finding the H.C.F. of a given set of
numbers:
Method I: Prime Factorisation method :
Express each one of the given numbers as the product of prime
factors. The product of least powers/index of common prime factors gives H.C.F.
Example I:Find the H.C.F. of 8 and 14 by Prime
Factorisation method?
Solution:
8 = 2 x 2 x 2
14 = 2 x 7
Common factor of 8 and 14 = 2.
Thus, Highest Common Factor (H.C.F.) of 8 and 14 = 2.
Example II:Find the H.C.F. of 24, 36 and 72 by
Prime Factorisation method?
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
72 = 2 x 2 x 2 x 3 x 3
H.C.F. of 24, 36 and 72 = Product of common factors with least
powers/index = 2^2 x 3
Thus, Highest Common Factor (H.C.F.) of 24, 36 and 72 = 12
Method II: Successive Division method :
Divide the larger number by the smaller one. Now, divide the
divisor by the remainder. Repeat the process of dividing the preceding number
by the remainder last obtained till zero is obtained as remainder. The last
divisor is the required H.C.F.
Example I:Find the H.C.F. of 8 and 14 by
Successive Division method?
8 | 14 | 1
8
6 | 8 | 1
6
2 | 6 | 3
6
0
Least Common Multiple (L.C.M.):
L.C.M. of two or more given numbers is the smallest number which
is divisible by all the given numbers.
Methods of finding the L.C.M. of a given set of
numbers:
Method I: Prime Factorisation method :
Express each one of the given numbers as the product of prime
factors. The product of greatest powers/index of common prime factors gives
L.C.M.
Example I:Find the L.C.M. of 8 and 14 by Prime
Factorisation method?
Solution:
8 = 2 x 2 x 2
14 = 2 x 7
L.C.M. of 8 and 14 = Product of all the prime factors of each of
the given number with greatest index of common prime factors
= 2^3 x 7 = 56.
Thus, L.C.M. of 8 and 14 = 56.
Method II: Division method :
Find the L.C.M. of 8 and 14 by using Division
method?
2 | 8, 14
|4, 7
L.C.M. of the given numbers = product of divisors and the
remaining numbers = 2 x 4 x 7 = 56.
Some important formula related to H.C.F.
and L.C.M.:
(1) H.C.F. of given fractions = H.C.F. of
numerator / L.C.M. of denominator
(2) L.C.M. of given fractions = L.C.M. of numerator
/ H.C.F. of denominator
(3) Product of two numbers (First number x Second Number) =
H.C.F. X L.C.M.
(4) H.C.F. of a given number always divides its L.C.M.
(5) Largest number which divides x, y, z to leave remainder R in
each case = H.C.F. of (x-R), (y-R), (z-R).
(6) Largest number which divides x, y, z to leave same remainder =
H.C.F. of (y-x), (z-y), (z-x).
(7) Largest number which divides x, y, z to leave remainder a,b,c =
H.C.F. of (x-a), (y-b), (z-c).
(8) Least number which when divided by x, y, z and leaves a
remainder R in each case = (L.C.M. of x, y, z) + R
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